H(x)=3x^2-2x+13

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Solution for H(x)=3x^2-2x+13 equation: 



(H)=3H^2-2H+13

We move all terms to the left:

(H)-(3H^2-2H+13)=0

We get rid of parentheses

-3H^2+H+2H-13=0

We add all the numbers together, and all the variables

-3H^2+3H-13=0

a = -3; b = 3; c = -13;
Δ = b2-4ac
Δ = 32-4·(-3)·(-13)
Δ = -147
Delta is less than zero, so there is no solution for the equation

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